NTA Abhyas JEE Main2020PhysicsMagnetic Effects of CurrentPractice
A conductor AB of length l carrying a current i is placed perpendicular to a long straight conductor XY carrying a current I as shown. The force on AB will be
Options
- Aμ 0 I i 2 π ln 2
- Bμ 0 I i 2 π ln 3
- C3 μ 0 I i 2 π
- D2 μ 0 I i 3 π
Correct answer
B. μ 0 I i 2 π ln 3
Step-by-step solution
d F = i d x B d F = i d x μ 0 I 2 π x F A B = ∫ l 2 3 l 2 μ 0 i I d x 2 π x F A B = μ 0 I i 2 π ln 3