NTA Abhyas JEE Main2020PhysicsMagnetic Effects of CurrentPractice
A proton accelerated by a potential difference V, moves through a transverse magnetic field B as shown in the figure. Then the angle θ through which the proton deviates from the initial direction of its motion is
Options
- Aθ = sin - 1 d B q V 2 m
- Bθ = sin - 1 d B q 2 m V
- Cθ = tan - 1 d B q V 2 m
- Dθ = tan - 1 d B q 2 m V
Correct answer
B. θ = sin - 1 d B q 2 m V
Step-by-step solution
B q v = m v 2 r 1 2 m v 2 = V q And sin ⁡ θ = d r r = m v q B = m q B   2 V q m sin ⁡ θ = d B q 2 m V θ = sin - 1 d B q 2 m V