A particle of charge per unit mass α is released from the origin with velocity v → = v 0 i ^ in the magnetic field B → = - B 0 k ^ for x ≤ 3 2 v 0 B 0 α and B → = 0 for x > 3 2 v 0 B 0 α The x-coordinate of the particle at time t > π 3 B 0 α would be

Step-by-step solution

r = mv 0 B 0 q = v 0 B 0 α , x r = 3 2 = sin θ ⇒ θ = 6 0 ∘ t OA = T 6 = π 3 B 0 α Therefore x-coordinate of particle at any time t > π 3 B 0 α will be x = 3 2 v 0 B 0 α + v 0 t - π 3 B 0 α cos 6 0 ∘ = 3 2 v 0 B 0 α + v 0 2 t - π 3 B 0 α