If at a distance of 40 cm at an axial position of a dipole, the "magnetic potential" (analogous to electric potential) is 2 .4 × 10 - 5 J A m - 1 , then the magnetic moment of the dipole is

Step-by-step solution

Here, r = 40   c m = 0.4   m θ = 0 ° (an axial line) M = ? As V = μ 0 4 π M   c o s θ r 2 ⇒ 2.4 × 10 - 5 = 10 - 7 × M × 1 0.4 2 ⇒ M = 38.4   A   m 2