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NTA Abhyas 2020
Exam
NTA Abhyas
Year
2020
Subject
Physics
Chapter
Magnetic Properties of Matter

NTA Abhyas 2020 · Physics · Magnetic Properties of Matter

A paramagnetic material shows a net& magnetization of 8 A m ^ -1...

A paramagnetic material shows a net& magnetization of 8Am−1{8 A m}^{-1} when placed in an& external magnetic field of intensity 0.6 T\text{0}\text{.6 T} at a& temperature of 4K\text{4}\text{K}. When the same material is placed in an external magnetic field of intensity 0.2 T\text{0}\text{.2 T} at a temperature of 16 K\text{16 K}, the& magnetization will be

Options

  1. A323Am−1\dfrac{32}{3}Am^{- 1}
  2. B23Am−1\dfrac{2}{3}Am^{- 1}
  3. C6Am−16Am^{- 1}
  4. D2.4Am−12.4Am^{- 1}

Correct answer

B. 23Am−1\dfrac{2}{3}Am^{- 1}

Step-by-step solution

According to Curie's law,

Magnetization, I∝MagneticInduction(B)Absolutetemperature(T)I ∝ \dfrac{MagneticInduction ( B )}{Absolutetemperature ( T )}

⇒I2I1=B2T1B1T2⇒ \dfrac{I2}{I1} = \dfrac{{B}_{2}{T}_{1}}{{B}_{1}{T}_{2}}

⇒I28=0.2×40.6×16⇒ \dfrac{I2}{8} = \dfrac{0. 2 \times 4}{0. 6 \times 16}

⇒I2=23Am−1⇒ {I}_{2} = \dfrac{2}{3}Am^{- 1}

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