NTA Abhyas JEE Main2020PhysicsMagnetic Properties of MatterPractice
A paramagnetic substance, in the form of a cube with sides 1 cm , has a magnetic dipole moment of 20 × 10 - 6 J T - 1 , when a magnetic intensity of 60 × 10 3 A m - 1 is applied. Its magnetic susceptibility is
Options
- A3.3 × 10 - 4
- B2.3 × 10 - 2
- C4.3 × 10 - 2
- D3.3 × 10 - 2
Correct answer
A. 3.3 × 10 - 4
Step-by-step solution
M = Magnetic moment per unit volume = 20 × 10 - 6 1 × 10 - 2 3 J T - 1 m - 3 = 20 J T - 1 m - 3 H = 60 × 10 3 A m - 1 χ = M H = 20 60 × 10 3 = 3.3 × 10 - 4