NTA Abhyas JEE Main2020PhysicsMagnetic Properties of MatterPractice
The horizontal component of the Earth's magnetic field is 3.6 × 10 - 5 T where the dip angle is 60 ° . The magnitude of the Earth's magnetic field is
Options
- A2.8 × 10 - 4 t e s l a
- B2.1 × 10 - 4 t e s l a
- C7.2 × 10 - 5 t e s l a
- D3.6 × 10 - 5 t e s l a
Correct answer
C. 7.2 × 10 - 5 t e s l a
Step-by-step solution
Horizontal component of Earth’s field, H = B cos θ , since, θ = 60 ° 3.6 × 10 − 5 = B × 1 2 ⇒ B = 7.2 × 10 − 5 tesla