The resultant of two vectors is perpendicular to first vector of...

The resultant of two vectors is perpendicular to first vector of magnitude

6N

. If the resultant has magnitude

6\sqrt{3}\text{N}

, then magnitude of second vector is The resultant of two vectors is perpendicular to first vector of magnitude 6N . If the resultant has magnitude 6 3 N ,

The resultant of two vectors is perpendicular to first vector of magnitude 6N . If the resultant has magnitude 6 3 N ,

Options

A $6\sqrt{2}N$
B $12N$
C $9\sqrt{3}N$
D $6\sqrt{3}N$

Correct answer

B. $12N$

Step-by-step solution

B Cos \theta = 6

B Sin\theta = 6\sqrt{3}

\text{B} = \sqrt{{6}^{2} + {\left(6\sqrt{3}\right)}^{2}} = 12

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