A piece of solid weighs 120 gm in open air, 90 gm in water and 60 gm in a liquid. The relative density of solid and that of liquid are respectively.

Step-by-step solution

According to question 120 = ρ V g .....(i) (where ρ is density of solid) 90 = ( ρ - ρ w ) V g ⇒ ρ w V g = 30 .....(ii) (where ρ w is density of water) 60 = ρ - ρ l V g ⇒ ρ l V g = 60 .....(iii) ) (where ρ l is density of water) Form (i), (ii), (iii) ρ ρ w = 120 30 = 4 1 ρ l ρ w = 60 30 = 2 1