NTA Abhyas JEE Main2020PhysicsMechanical Properties of FluidsPractice
A conical portion of radius R and height H is removed from the bottom of a cylinder of radius R . The volume of the remaining cylinder is V and its mass is M . It is suspended by a string in a liquid of density ρ where it stays vertical. The upper surface of the cylinder is at a depth h below the liquid surface. The force on the bottom of the cylinder by the liquid is
Options
- AMg
- BMg - Vρg
- CMg + πR 2 hρg
- Dρg V + πR 2 h
Correct answer
D. ρg V + πR 2 h
Step-by-step solution
Net pressure force = weight of liquid displaced ⇒ F - ρghπR 2 = ρgV ⇒ F = ρg V + πR 2 h