A sniper fires a rifle bullet into a gasoline tank making a hole 53.0 m below the surface of gasoline. The tank was sealed at 3.10 a t m . The stored gasoline has a density of 660 k g m - 3 . The velocity with which gasoline begins to shoot out of the hole is

Step-by-step solution

According to Bernoulli's theorem, P B + h ρ g = P A + 1 2 ρ v A 2   A s   v A > > v B 3.10 P + 53 × 660 × 10 = P + 1 2 × 660 v A 2 ⇒ 2.1 × 1.01 × 10 5 + 3.498 × 10 5 = 1 2 × 660 × v A 2 ⇒ 5.619 × 10 5 = 1 2 × 660 × v A 2 ∴   v A = 2 × 5.619 × 10 5 660 = 41   m   s - 1