NTA Abhyas JEE Main2020PhysicsMechanical Properties of FluidsPractice
The pressures inside two soap bubbles are 1.02 a t m and 1.03 a t m respectively. The ratio of their volumes is
Options
- A102 : 103
- B8 : 27
- C103 3 : 102 3
- D27 : 8
Correct answer
D. 27 : 8
Step-by-step solution
P i n -   P a t m =   e x c e s s   p r e s s u r e = 4 T R P atm =1 atm ∴   R 1 R 2 = Δ P 2 Δ P 1 =   3 2 ∴   V 1 V 2 =   R 1 3 R 2 3 = 27 8