NTA Abhyas JEE Main2020PhysicsMechanical Properties of FluidsPractice
The lower end of a glass capillary tube is dipped in water. Water rises to a height of 9 cm . The tube is then broken at a height of 5 cm . The height of the water column and angle of contact will be
Options
- A5   cm ,   cos - 1 ⁡ 5 9
- B4   cm ,   cos - 1 ⁡ 5 4
- C5   cm ,   cos - 1 ⁡ 9 5
- D5   cm ,   cos - 1 ⁡ 6 7
Correct answer
A. 5   cm ,   cos - 1 ⁡ 5 9
Step-by-step solution
When a capillary tube is broken at a height 5 cm, meaning that water will rise to height 5   cm , hence h 2 = 5   cm . Since, we know, for capillarity phenomenon h = 2 S c o s θ r ρ g , where symbols have their usual meaning. or h c o s θ = constant Thus, h 1 c o s θ 1 = h 2 c o s θ 2 ⇒ 9 c o s θ = 5 c o s θ 2 [for glass θ 1 = 0 ] ⇒ c o s θ 2 = 5 9 ∵   c o s 0 o = 1 ∴ θ 2 = c o s - 1 5 9