NTA Abhyas JEE Main2020PhysicsMechanical Properties of FluidsPractice
In a cylinder-piston arrangement, the air is under a pressure P 1 . A soap bubble of radius r lies inside the cylinder. Soap bubble has surface tension T . The radius of soap bubble is to be reduced to half. Find the pressure P 2 to which air should be compressed isothermally.
Options
- AP 1 + 4 T r
- B4 P 1 + 1 2 T r
- C8 P 1 + 2 4 T r
- DP 1 + 2 T r
Correct answer
C. 8 P 1 + 2 4 T r
Step-by-step solution
Using P i V i = P f V f (for the air bubble) we have P 1 + 4 T r 4 3 π r 3 = P 2 + 4 T r / 2 4 3 π r 2 3 Solving this, we get P 2 = 8 P 1 + 2 4 T r