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A liquid is kept in a cylindrical vessel which is rotated along its axis. The liquid rises at its sides. If the radius of the vessel is 0.05 m and the speed of rotation is 2 rev s - 1 , the difference in the height of liquid at the centre of the vessel and its sides is

Options

  1. A0.001   m
  2. B0.002 m
  3. C0.01 m
  4. D0.02 m

Correct answer

D. 0.02 m

Step-by-step solution

h = r 2 ω 2 2 g h = 0.05 2 2 × 2 π 2 2 × g = 0.02 m

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