NTA Abhyas JEE Main2020PhysicsMechanical Properties of FluidsPractice
A slender homogeneous rod of length 2L floats partly immersed in water, being supported by a string fastened to one of its ends, as shown in the figure. The specific gravity of the rod is 0.36. The length of the rod that extends out of the water is K L 10 . Find the value of K.
Correct answer
16
Step-by-step solution
Balancing torque about end A M g L c o s θ = B l + 2 L - l 2 c o s θ M g L = ρ . ( 2 L - l ) A g 2 L + l 2 0.36 × 2 L 2 = 4 L 2 - l 2 2 1.44 L 2 = 4 L 2 - l 2 l 2 = 4 L 2 - 1.44 L 2 l 2 = 2.56 L 2 l = 16 10 L ∴ K = 16