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Two metal strips are riveted together at their ends by four rivets, each of diameter 6   mm . Assuming that each of the rivets carries one-quarter of the load, the maximum tension that can be produced in the riveted strip is [Breaking shear stress of the rivet = 6 .9 × 10 7   Pa ]

Options

  1. A7.8 × 10 3 N
  2. B6.9 × 10 3 N
  3. C3.14 × 10 3   N
  4. Dnone of these

Correct answer

A. 7.8 × 10 3 N

Step-by-step solution

Diameter of each rivet ( D ) = 6 mm ∴ Radius (r) = D 2 = 3 mm = 3 × 10 - 3 m Maximum shearing stress on each rivet = 6.9 × 10 7 Pa Let w be the maximum load that can be subjected to the riveted strip. As each rivet carry one-quarter of the load, therefore Load on each rivet = w 4 Maximum shearing stress = Maximum shearing force Area ∴ 6.9 × 10 7 = w / 4 π r 2 or w = 6.9 × 10 7 4 πr 2 ​or w = 6.9 × 10 7 × 4 × 3.1 4 × ( 3 × 10 − 3 ) 2 = 6.9 × 4 × 3.14 × 9 × 10 = 7.8 × 10 3 N

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