A particular force F applied on a wire increases its length by 2 × 10 - 3 m . If we were to increase the wire's length by 4 × 10 - 3 m , then the applied force is n F . What is the value of n ?

Step-by-step solution

Y = F A l L = F × L A × l [ l = Change in length, L = Original length] (where Y is Young's modulus of elasticity) Since Y , L and A remain same. ⇒ F ∝ l ⇒ F 1 F 2 = l 1 l 2 ⇒ F F 2 = 2 × 10 - 3 4 × 10 - 3 ⇒ F 2 = 2 F ⇒ F 2 = n F ⇒ n = 2