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NTA Abhyas 2020
Exam
NTA Abhyas
Year
2020
Subject
Physics
Chapter
Mechanical Properties of Solids

NTA Abhyas 2020 · Physics · Mechanical Properties of Solids

A heavy plank of mass 100 kg hangs on three vertical wires of equal...

A heavy plank of mass 100100 kg hangs on three vertical wires of equal length arranged symmetrically (see figure). All the wires have the same cross-section. The middle wire is of steel and the other two are of copper. The modulus of elasticity of steel is assumed to be double that of copper. Determine the tensions in the wire. ( use g=9.8ms−2g = 9. 8ms^{- 2}& )

A heavy plank of mass 100 kg hangs on three vertical wires of equal length arranged symmetrically (see figure). All the

Options

  1. ATcu=245N{T}_{cu} = 245N, Tsteel=490N{T}_{steel} = 490N
  2. BTcu=235N{T}_{cu} = 235N, Tsteel=490N{T}_{steel} = 490N
  3. CTcu=205N{T}_{cu} = 205N, Tsteel=490N{T}_{steel} = 490N
  4. DTcu=295N{T}_{cu} = 295N, Tsteel=420N{T}_{steel} = 420N

Correct answer

A. Tcu=245N{T}_{cu} = 245N, Tsteel=490N{T}_{steel} = 490N

Step-by-step solution

Let tension in copper and steel wires are& Tcuand{T}_{cu} and{T}_{st}.Assumingsamestrain(duetoheavyplank)wenotethat<br/><br/>. Assuming same strain (due to heavy plank) we note that<br /><br />{Y}_{steel} = \dfrac{T{}_{st}L }{A \left(\Delta L \right)} and&

or& TstTcu=YsteelYcu=2(given)or\dfrac{T{}_{st}}{T{}_{cu}} = \dfrac{Y{}_{steel}}{Y{}_{cu}} = 2 \left(\text{given}\right)or T{}_{st} = 2T{}_{cu}<br/><br/>Further,<br /><br />Further,{T}_{st} + 2{T}_{cu} = 100kg ( given )<br/><br/><u><strong><imgalt=""src="/api/proxy−image?url=https<br /><br /><u><strong><img alt="" src="/api/proxy-image?url=https%3A%2F%2Ffirebasestorage.googleapis.com%2Fv0%2Fb%2Fquantrexacademy-app.firebasestorage.app%2Fo%2Fquestions%252Ffigs%252Fnta_abhyas%252Fjee_main%252Fimages%252FEM0014785_AnsExp1_1.jpg%3Falt%3Dmedia \text{ and } clean=1 \text{ and } v=wm2" data-qx-orig-src="https://firebasestorage.googleapis.com/v0/b/quantrexacademy-app.firebasestorage.app/o/questions%2Ffigs%2Fnta_abhyas%2Fjee_main%2Fimages%2FEM0014785_AnsExp1_1.jpg?alt=media" data-qx-storage-src="https://firebasestorage.googleapis.com/v0/b/quantrexacademy-app.firebasestorage.app/o/questions%2Ffigs%2Fnta_abhyas%2Fjee_main%2Fimages%2FEM0014785_AnsExp1_1.jpg?alt=media" style="width: 310px; height: 216px;" /></strong></u><br /><br />or2{T}_{cu} + 2{T}_{cu} = 100kg or Tcu=25kg{T}_{cu} = 25kg

And therefore, Tst=2Tcu=50kg{T}_{st} = 2{T}_{cu} = 50kg

Thus Tcu{T}_{cu} is & Tcu=25kgf=245N{T}_{cu} = 25kgf = 245N

and& Tst=50kgf=490N{T}_{st} = 50kgf = 490N

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