A wire suspended vertically from one of its ends is stretched by attaching a weight of 200 N to the lower end. The weight stretches the wire by 1 mm . Then the elastic energy stored in the wire is

Step-by-step solution

Elastic energy per unit volume = 1 2 × stress × strain ∴ Elastic energy = 1 2 × stress × strain × volume   = 1 2 × F A × Δ L L × AL = 1 2 F Δ L = 1 2 × 200 × 10 - 3 =0.1 J