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NTA Abhyas 2020
Exam
NTA Abhyas
Year
2020
Subject
Physics
Chapter
Motion in One Dimension

NTA Abhyas 2020 · Physics · Motion in One Dimension

Two objects P and Q , travelling in the same direction start from...

Two objects PP and QQ, travelling in the same direction start from rest. While the object PP starts at time t=0t = 0 and object QQ starts later at t=30mint = 30min. The object PP has an acceleration of 40km/h240km / h^{2}. To catch PP at a distance of 2020 km, the acceleration of QQ should be

Options

  1. A40km/h240km / h^{2}
  2. B80km/h280km / h^{2}
  3. C100km/h2100km / h^{2}
  4. D160km/h2160km / h^{2}

Correct answer

D. 160km/h2160km / h^{2}

Step-by-step solution

According to question,

Object PP starts at t=0t = 0 and acceleration of P=40km/h2P = 40km / h^{2}

The time taken by object PP to cover 2020 km will be,

s=ut+12at2s = ut + \dfrac{1}{2}{at}^{2}

Where, u=0,s=12at2u = 0, s = \dfrac{1}{2}{at}^{2}

t=2sat = \sqrt{\dfrac{2s}{a}}

Here, a=40km/h2a = 40km / h^{2}

and s=20kms = 20km

t=2×2040t = \sqrt{\dfrac{2 \times 20}{40}}

=1hour= 1hour

Time taken by QQ will be 12hour\dfrac{1}{2}hour, because it started after 30min30min.

The acceleration in QQ,

a=2st2=2×20(12)2a = \dfrac{2s}{t2} = \dfrac{2 \times 20}{\left(\dfrac{1}{2}\right)2}

=2×4×20= 2 \times 4 \times 20

=160km/h2= 160km / h^{2}
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