NTA Abhyas 2020
- Exam
- NTA Abhyas
- Year
- 2020
- Subject
- Physics
- Chapter
- Motion in One Dimension
NTA Abhyas 2020 · Physics · Motion in One Dimension
A particle moves along a straight line with a variable acceleration...
A particle moves along a straight line with a variable acceleration given in the acceleration-displacement curve as shown in the figure. Determine the velocity (in ) of the particle after it has travelled a distance of . The initial velocity is .

Correct answer
20
Step-by-step solution
Area under curve is
……..(i)
Area under the curve is also equal to …….(ii)
From (i) and (ii)
\left({v}^{2} - {u}^{2}\right) =300{v}^{2} = {u}^{2} + 300{v}^{2} = {\left(10\right)}^{2} + 300v = \sqrt{400} = 20\text{m}{s}^{- 1}