A particle leaves the origin with an initial velocity v → = 3.00 i ^ ms - 1 and a constant acceleration a → = - 1.00 i ^ - 0.5 j ^ ms - 2 . When the particle reaches it maximum x -coordinate, what is the magnitude of its velocity (in m/s) i

Question

A particle leaves the origin with an initial velocity v → = 3.00 i ^ ms - 1 and a constant acceleration a → = - 1.00 i ^ - 0.5 j ^ ms - 2 . When the particle reaches it maximum x -coordinate, what is the magnitude of its velocity (in m/s) in y -direction?

Quantrex Academy · Accepted Answer

Correct answer: 1.5

Velocity along x direction is v x = v 0 2 + at v x = 3 + - 1 t so when particle reach maximum x coordinate v x = 0 ⇒ t = 3 sec similarly v y = v 0 y + a y t v y = 0 + - 1 2 t v y at t = 3 = - 3 2 = - 1 . 5 m s - 1

A particle leaves the origin with an initial velocity v → = 3.00 i ^ ms - 1 and a constant acceleration a → = - 1.00 i ^ - 0.5 j ^ ms - 2 . When the particle reaches it maximum x -coordinate, what is the magnitude of its velocity (in m/s) in y -direction?

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