NTA Abhyas 2020
- Exam
- NTA Abhyas
- Year
- 2020
- Subject
- Physics
- Chapter
- Motion in One Dimension
NTA Abhyas 2020 · Physics · Motion in One Dimension
A particle leaves the origin with an initial velocity → v = (3.00 ^...
A particle leaves the origin with an initial velocity \overset{\to}{\text{v}} = \left(\text{3.00} \overset{^}{\text{i}}\right) {\text{ms}}^{- 1} and a constant acceleration \overset{\to}{\text{a}} = \left(- \text{1.00} \overset{^}{\text{i}} - \text{0.5} \overset{^}{\text{j}}\right) {\text{ms}}^{- 2} . When the particle reaches it maximum -coordinate, what is the magnitude of its velocity (in m/s) in -direction?
Correct answer
1.5
Step-by-step solution
Velocity along direction is
so when particle reach maximum coordinate
similarly
so when particle reach maximum coordinate
similarly