Exam

NTA Abhyas

Year

2020

Subject

Physics

Chapter

Motion in One Dimension

NTA Abhyas 2020 · Physics · Motion in One Dimension

Displacement x versus t^ 2 graph is shown for a particle. The...

Displacement $x$ versus $t^{2}$ graph is shown for a particle. The acceleration of the particle is

Step-by-step solution

From the graph,

$x = Slope ( t^{2} )$

$x = \dfrac{2 - 0}{1 - 0} ( t^{2} )$

$x = 2t^{2}$

$\dfrac{dx}{dt} = 4t$

$\dfrac{d^{2}x}{dt^{2}} = 4$

a = 4ms^{- 2} \left[∵ \dfrac{d^{2}x}{dt^{2}} = a\right]