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NTA Abhyas JEE Main2020PhysicsMotion in One DimensionPractice

Displacement x versus t 2 graph is shown for a particle. The acceleration of the particle is

Options

  1. A4   m   s - 2
  2. B8   m   s - 2
  3. CZero
  4. D2   m   s - 2

Correct answer

A. 4   m   s - 2

Step-by-step solution

From the graph, x = S l o p e ( t 2 ) x = 2 - 0 1 - 0 ( t 2 ) x = 2 t 2 d x d t = 4 t d 2 x d t 2 = 4 a = 4  m   s - 2   ∵       d 2 x d t 2 = a

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