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NTA Abhyas JEE Main2020PhysicsMotion in One DimensionPractice

The following figure gives the movement of an object. Select the correct statement from the given choices.

Options

  1. AThe total distance travelled by the object is 975 m
  2. BThe maximum acceleration of the object is 2   m   s - 2
  3. CThe maximum deceleration happened between 25 th and 35 th seconds
  4. DThe object was at rest between 10 th and 15 th seconds

Correct answer

A. The total distance travelled by the object is 975 m

Step-by-step solution

The total distance travelled by the object will be area of given graph in the figure. Total distance s = 75 + 225 + 125 + 100 + 400 + 50 = 975 m

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