NTA Abhyas JEE Main2020PhysicsMotion in One DimensionPractice
A body released from a great height falls freely towards the earth. Another body is released from the same height exactly one second later. The separation (in m ) between the two bodies two seconds after the release of the second body is ( g = 9 . 8 m s - 2 )
Correct answer
24.5
Step-by-step solution
Separation of the body after t second after the release of 1st body is ∆ x = 1 2 g t 2 - 1 2 g t - 1 2 = 1 2 g t 2 - t - 1 2 = 1 2 g 2 t - 1 t = 2 + 1 = 3 ∆ x = 1 2 × 9.8 × 5 m = 24 . 5   m