A body released from a great height falls freely towards the earth. Another body is released from the same height exactly one second later. The separation (in m ) between the two bodies two seconds after the release of

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Quantrex Academy · Accepted Answer

Correct answer: 24.5

Separation of the body after t second after the release of 1st body is ∆ x = (1)/(2)g t ^ 2 - (1)/(2)g (t - 1) ^ 2 = (1)/(2)g[ t ^ 2 - (t - 1) ^ 2 ] = (1)/(2)g(2t - 1) t = 2 + 1 = 3 ∆ x = (1)/(2) × 9.8 × 5m = 24 . 5m

A body released from a great height falls freely towards the earth....

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