A balloon rises from rest with a constant acceleration of (g)/(8) . A stone is released from it when it has risen to height h . The time taken by the stone to reach the ground is n (h)/(g) seconds. Then what is the

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Correct answer: 2

From equation v ^ 2 = u ^ 2 + 2as Given, u = 0, a = (g)/(8) ∴ We have, v = 2((g)/(8))h When the stone released from this balloon. It will go upward with velocity v = gh In this condition, time taken by stone to reach the ground, - h = vt - (1)/(2) g t ^ 2 t = (v)/(g)[1 + 1 + 2gh v ^ 2 ] = gh 2 g [1 + 1 + (2gh)/((gh)/(4)) ] = 2 gh g = 2 (h)/(g)

A balloon rises from rest with a constant acceleration of (g)/(8) ....

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