NTA Abhyas JEE Main2020PhysicsMotion in One DimensionPractice
The retardation experienced by a moving motorboat, after its engine is cut off, is given by d v d t = - k v 3 , where k is a constant. If v 0 is the magnitude of the velocity at cut-off, the magnitude of the velocity at time t after the cut-off is
Options
- Av 0
- Bv 0 2
- Cv 0 e - k t
- Dv 0 2 v 0 2 k t + 1
Correct answer
D. v 0 2 v 0 2 k t + 1
Step-by-step solution
d v d t = - k v 3 ⇒ - ∫ v 0 v d v k v 3 = ∫ 0 t d t ⇒ 1 k ∫ v 0 v - v - 3 d v = t or - 1 k v - 3 + 1 - 3 + 1 v 0 v = t or 1 2 k 1 v 2 - 1 v 0 2 = t or 1 v 2 - 1 v 0 2 = 2 k t or 1 v 2 = 1 v 0 2 + 2 k t or 1 v 2 = 1 + 2 v 0 2 k t v 0 2 or v = v 0 2 v 0 2 k t + 1