NTA Abhyas JEE Main2020PhysicsMotion in One DimensionPractice
A body starts from rest and is uniformly accelerated for 30 s . The distance travelled in the first 10 s is S 1 , next 10 s is S 2 and the last 10 s is S 3 . Then S 1 : S 2 : S 3 is the same as
Options
- A1   :   2   :   4
- B1   :   2   :   5
- C1   :   3   :   5
- D1   :   3   :   9
Correct answer
C. 1   :   3   :   5
Step-by-step solution
a = constant S 1 = v 0 t + 1 2 a t 2 v 1 = v 0 + a t S 2 = v 1 t + 1 2 at 2 ⇒ v 0 t + 3 2 a t 2 v 2 = v 1 + at = v 0 + 2 at S 3 = v 2 t + 1 2 at 2 = v 0 t + 5 2 at 2 v 0 = 0 S 1 = 1 2 at 2 ; S 2 = 3 2 at 2 ; S 3 = 5 2 at 2 S 1  :  S 2  :  S 3 = 1  :  3  :  5