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NTA Abhyas 2020
Exam
NTA Abhyas
Year
2020
Subject
Physics
Chapter
Motion in Two Dimensions

NTA Abhyas 2020 · Physics · Motion in Two Dimensions

A cyclist riding the bicycle at a speed of 14 3 ms^ - 1 takes a...

A cyclist riding the bicycle at a speed of 143ms−114\sqrt{3}ms^{- 1} takes a turn around a circular road of radius 203m20\sqrt{3}m without skidding. Given g=9.8ms−2g = 9.8ms^{- 2}& What is his inclination to the vertical ?

Options

  1. A30°30 °
  2. B90°90 °
  3. C45o{45}^{o}
  4. D60°60 °

Correct answer

D. 60°60 °

Step-by-step solution

θ=tan−1(v2rg)=tan−1[(143)2203×9.8]=tan−1[3]=60°\theta = tan^{- 1}\left(\dfrac{v2}{rg}\right) = tan^{- 1}\left[\dfrac{( 14\sqrt{3}{)}^{2}}{20\sqrt{3} \times 9.8}\right] = tan^{- 1} [ \sqrt{3} ] = 60 °
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