Two stones are thrown up simultaneously from the edge of cliff with initial speeds v and 2 v . The relative position of the second stone with respect to first varies with time till both the stones strike the ground as

Step-by-step solution

Initially when both are in air, the relative acceleration between them is zero. Therefore, relative position verus-time graph is a straight line. S 1 = vt - 1 2 g t 2 S 2 = 2 vt - 1 2 g t 2 S 21 = S 2 - S 1 S 21 = vt Once the first ball reaches the ground, its acceleration becomes zero. Therefore, the relative acceleration is now g and the graph is parabolic. S 2 = 2 vt - 1 2 g t 2