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NTA Abhyas 2020
Exam
NTA Abhyas
Year
2020
Subject
Physics
Chapter
Motion in Two Dimensions

NTA Abhyas 2020 · Physics · Motion in Two Dimensions

A horizontal smooth square platform ABCD is moving towards the...

A horizontal smooth square platform ABCDABCD is moving towards the right with a uniform speed vv. At what angle θ\theta must a particle slide from AA, on the platform, with speed uu so that it strikes the point BB? (Assume uu to be uniform and u>vu > v)

A horizontal smooth square platform ABCD is moving towards the right with a uniform speed v . At what angle θ must a

Options

  1. Asin−1(uv){\text{sin}}^{-1}\left(\dfrac{u}{v}\right)
  2. Bcos−1(vu){\text{cos}}^{-1}\left(\dfrac{v}{u}\right)
  3. Ccos−1(uv){\text{cos}}^{-1}\left(\dfrac{u}{v}\right)
  4. Dsin−1(vu){\text{sin}}^{-1}\left(\dfrac{v}{u}\right)

Correct answer

B. cos−1(vu){\text{cos}}^{-1}\left(\dfrac{v}{u}\right)

Step-by-step solution

A horizontal smooth square platform ABCD is moving towards the right with a uniform speed v . At what angle θ must a

⇒ucosθt=vt⇒ \text{u} \text{cos} \theta \text{t} = \text{v} \text{t}

⇒ucosθ=v⇒ \text{u} \text{cos} \theta = \text{v}

cosθ=vu\text{cos} \theta = \dfrac{\text{v}}{\text{u}}

\theta = {\text{cos}}^{-1} \left(\dfrac{\text{v}}{\text{u}}\right)
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