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NTA Abhyas JEE Main2020PhysicsMotion in Two DimensionsPractice

A ball is projected from the ground at an angle θ with the horizontal. After 1 s it is moving at an angle 45 ° with the horizontal and after 2 s , it is moving horizontally. What is the velocity of projection of the ball?

Options

  1. A10 3   m   s - 1
  2. B20 3   m   s - 1
  3. C10 5 m s - 1
  4. D20 2 m s - 1

Correct answer

C. 10 5 m s - 1

Step-by-step solution

The ball will be vertical at the highest point so t u p =   u s i n θ g = 2   ⇒ u s i n θ = 20       . .   … … .(1) ∵   ta n α = u s i n θ - g t u   c o s θ ⇒ 1 = 20 - g ( 1 ) u c o s θ ⇒ u c o s θ = 10 … . .(2) Squaring and adding equation (1) & equation (2), we get u s i n θ 2 + u cos θ 2 = 20 2 + 10 2 ⇒       u 2 = 500 ⇒   u = 10 5   m   s - 1

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