Two tall buildings are 40m apart. With what speed must a ball be thrown horizontally from a window 145m above the ground in one building, so that it will enter a window 22. 5m & above from the ground in the other?

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Quantrex Academy · Accepted Answer

Correct answer: B. 8ms^ - 1

Given, u _ x = v and u _ y = 0 Separating the motion in x and y directions Using x = u _ x t + (1)/(2)at^ 2 40 = vt (i) ⟹ t = (40)/(v) (ii) y= h _ net = 145 - 22.5 Using y = u _ y t + (1)/(2)at^ 2 122.5 = 0 + (1)/(2) × 10t^ 2 122.5 = 5 ((40)/(v)) ^ 2 v = 40 (5)/(122.5) = 8ms^ - 1 &

Two tall buildings are 40m apart. With what speed must a ball be...

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