Two seconds after projection, a projectile is traveling in a direction inclined at 30 ° to the horizontal. After one more sec, it is traveling horizontally, the magnitude and direction of its velocity are

Step-by-step solution

Let in 2s body reaches upto point A and after one more second upto point B. Total time of ascent for a body is given as 3s i.e., u sin ⁡ θ g = 3 ∴ u sin ⁡ θ = 10 × 3  = 30 ......(i) Horizontal component of velocity remains always constant u cos ⁡ θ = v cos ⁡ 30 ° .......(ii) For vertical upward motion between point O and A v sin ⁡ 30 o = u sin ⁡ θ - g × 2 [Using v = u - gt] v sin ⁡ 30 o = 30 - 20 A s   u sin ⁡ θ