NTA Abhyas JEE Main2020PhysicsMotion in Two DimensionsPractice
Velocity of a particle moving in a straight line varies with its displacement as v = 4 + 4 s m/s . Displacement of particle at time t = 0 is s = 0. Find displacement of particle at time t = 2 s.
Options
- A8 m
- B6 m
- C4 m
- D10 m
Correct answer
A. 8 m
Step-by-step solution
as a = vdv ds = 4 + 4s 1 2 4 + 4s × 4 = 2 , which is constant so we can use equation of motion now Squaring the given equation, we get v 2 = 4 + 4s Now, comparing it with v 2 = u 2 + 2as we get, u = 2 m/s and a = 2 m/s 2 ∴ Displacement at t = 2s is s = ut + 1 2 at 2 or s = 2 2 + 1 2 2 2 2 or s = 8 m