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NTA Abhyas JEE Main2020PhysicsMotion in Two DimensionsPractice

The equation of motion of a projectile is y = 12 x - 3 4 x 2 , where x and y are in metre. What is the range (in m ) of the projectile?

Correct answer

16

Step-by-step solution

y = 12 x - 3 4 x 2 Range is the point where y = 0 thus 0 = 12 x - 3 4 x 2 ⇒ x = 0 or x = 16 m

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