Exam

NTA Abhyas

Year

2020

Subject

Physics

Chapter

Motion in Two Dimensions

NTA Abhyas 2020 · Physics · Motion in Two Dimensions

The equation of motion of a projectile is y = 12x - (3)/(4) x ^ 2 ,...

The equation of motion of a projectile is $y = 12x - \dfrac{3}{4}{x}^{2}$, where $x$ and $y$ are in metre. What is the range (in $m$) of the projectile?

Step-by-step solution

$y = \text{12} x - \dfrac{3}{4} {x}^{2}$



Range is the point where $y = 0$

thus $0 = \text{12} x - \dfrac{3}{4} {x}^{2}$

$⇒$ $x = 0$

or $x = \text{16} m$