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NTA Abhyas JEE Main2020PhysicsMotion in Two DimensionsPractice

Two identical balls P and Q are projected with same speeds in a vertical plane from the same point O making projection angles with horizontal 30 ° and 60 ° , respectively and they fall directly on the plane A B at points P ′ and Q ′ respectively. Which of the following statement is true about distances as given in options?

Options

  1. AA P ′ > A Q ′
  2. BA P &prime; < A Q &prime;
  3. CA P &prime; ≤ A Q &prime;
  4. DAs there are complimentary projection angles A P &prime; = A Q &prime;

Correct answer

A. A P ′ > A Q ′

Step-by-step solution

Given, Projection angle of ball P = 30 &#176; Projection angle of ball Q = 60 &#176; According to the question, For complimentary angles ranges, O N is same for P and Q as O and N are on same horizontal plane. From figure A P &#8242; &#62; A Q &#8242;

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