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NTA Abhyas 2020
Exam
NTA Abhyas
Year
2020
Subject
Physics
Chapter
Motion in Two Dimensions

NTA Abhyas 2020 · Physics · Motion in Two Dimensions

Two identical balls P and Q are projected with same speeds in a...

Two identical balls PP and QQ are projected with same speeds in a vertical plane from the same point OO making projection angles with horizontal 30°30 ° and 60°60 °, respectively and they fall directly on the plane ABAB at points P′P^{′} and Q′Q^{′} respectively. Which of the following statement is true about distances as given in options?

Two identical balls P and Q are projected with same speeds in a vertical plane from the same point O making projection

Options

  1. AAP′>AQ′AP^{′} > AQ^{′}
  2. BAP^{&prime;} < AQ^{&prime;}
  3. CAP^{&prime;} \le AQ^{&prime;}
  4. DAs there are complimentary projection angles AP^{&prime;} = AQ^{&prime;}

Correct answer

A. AP′>AQ′AP^{′} > AQ^{′}

Step-by-step solution

Given,

Projection angle of ball P=30°P = 30 °

Projection angle of ball Q=60°Q = 60 °

According to the question,

Two identical balls P and Q are projected with same speeds in a vertical plane from the same point O making projection

For complimentary angles ranges, ONON is same for PP and QQ as OO and NN are on same horizontal plane. From figure AP′>AQ′AP^{′} > AQ^{′}
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