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NTA Abhyas 2020
Exam
NTA Abhyas
Year
2020
Subject
Physics
Chapter
Nuclear Physics

NTA Abhyas 2020 · Physics · Nuclear Physics

A solution containing active cobalt Co 2760 having an activity of...

A solution containing active cobalt Co2760Co 2760 having an activity of 0.8μCi0.8 \mu Ci and decay constant λ\lambda is injected in an animal's body. When 1cm31cm^{3} blood is drawn from the animal's body after 10h10h of injection, the activity was found to be 300dpm300dpm(decays per minute), then the total volume of blood in the animal's body is close to [1Ci=3.7×1010dps[ 1Ci = 3.7 \times {10}^{10}dps(decays per second) and at t=10ht = 10h the value of e−\lambdat=0.84]e^{- \lambdat} = 0.84 ]

Options

  1. A4L4L
  2. B6L6L
  3. C5L5L
  4. D7L7L

Correct answer

C. 5L5L

Step-by-step solution

Let total volume of blood is v\text{v}, initial activity A0=0.QμCi{A}_{0} = 0 . Q\mu{C}_{i} its activity at time t\text{t}

A=Aoe−\lambdatA = {A}_{o} e^{- \lambdat}

activity of x\text{x} volume

A1=(AV)X=XA^{1} = \left(\dfrac{A}{V}\right)X = X\left(\dfrac{{A}_{o}}{V}\right) e^{- \lambdat}<br/><br/><br /><br />V = X \left(\dfrac{{A}_{0}}{A^{1}}\right)e−\lambdate^{- \lambdat}

V=(1cm3)(8×10−7×3.7×101030060)(0.84)V = \left(1cm^{3}\right)\left(\dfrac{8 \times {10}^{- 7} \times 3.7 \times {10}^{10}}{\dfrac{300}{60}}\right)\left(0.84\right)

=4.97×103cm2=4.97= 4.97 \times {10}^{3}cm^{2} = 4.97 litre
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