The ratio of the nuclear radius, of an atom with mass number A and _ 2 ^ 4 He is (14)(1)/(3) . What is the value of A ?

Correct answer: 56 From the relation r &prop; A ^ 1 / 3 , we have, r _ 2 r _ 1 = ( A _ 2 A _ 1 ) ^ 1 / 3 or ( A _ 2 4 ) ^ 1 / 3 = (1 4) ^ 1 / 3 Therefore, A 2 = 56

NTA Abhyas 2020

Exam: NTA Abhyas
Year: 2020
Subject: Physics
Chapter: Nuclear Physics

NTA Abhyas 2020 · Physics · Nuclear Physics

The ratio of the nuclear radius, of an atom with mass number A and...

The ratio of the nuclear radius, of an atom with mass number A and

{}_{2}^{4} \text{He}

is \left(14\right)\dfrac{1}{3}

. What is the value of

A$?

Correct answer

Step-by-step solution

From the relation

\text{r} &prop; {\text{A}}^{1 / 3} \text{,}

we have,

\dfrac{{\text{r}}_{2}}{{\text{r}}_{1}} = {\left(\dfrac{{\text{A}}_{2}}{{\text{A}}_{1}}\right)}^{1 / 3}

{\left(\dfrac{{\text{A}}_{2}}{4}\right)}^{1 / 3} = {\left(1 4\right)}^{1 / 3}

Therefore, A₂ = 56

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