NTA Abhyas JEE Main2020PhysicsRay OpticsPractice
A microscope is having objective of focal length 1 cm and eyepiece of focal length 6 cm . If tube length is 30 cm and image is formed at the least distance of distinct vision, what is the magnification produced by the microscope. (Take D = 25 cm )
Options
- A6
- B155
- C25
- D125
Correct answer
B. 155
Step-by-step solution
For a compound microscope, m = L f 0 1 + D f e (Where length of tube L = 30 cm , focal length of objective lens f 0 = 1 cm , focal length of eye-piece f e = 6 cm , D = 25 cm ) ⇒ m = 30 1 1 + 25 6 = 30 × 6 + 25 6 ⇒ m = 5 × 31 ⇒ m = 155