NTA Abhyas JEE Main2020PhysicsRay OpticsPractice
A ray of light is incident normally on one of the faces of a prism of apex angle 30 ° and refractive index 2 . The angle of deviation of the ray is
Options
- A30 °
- B45 °
- C15 °
- Dnone of these
Correct answer
C. 15 °
Step-by-step solution
Using Snell’s law for the refraction at AC, we get μ sini = ( 1 ) sinr 2 sin 30 ° = sinr sinr = 1 2 ⇒ r = 45 ° ∴ Angle of deviation = 45 ° − 30 ° = 15 ° .