NTA Abhyas JEE Main2020PhysicsRay OpticsPractice
A thin prism of angle 5 ° is placed at a distance of 10 cm from the object. The distance of the image from the object is (given μ of prism = 1.5 )
Options
- Aπ 8   cm
- Bπ 12   cm
- C5π 36 cm
- Dπ 7   cm
Correct answer
C. 5π 36 cm
Step-by-step solution
δ = μ -1 A δ = 1.5 -1 × 5 ° = 2.5° = 2.5 × π 1 8 0 = π 72 δ≈tan δ = d 10 π 72 = d 10 ⇒ d = 5 π 36   cm