NTA Abhyas JEE Main2020PhysicsRay OpticsPractice
A point object is moving with a speed v in front of an arrangement of two mirrors as shown in the figure. The magnitude of velocity of the image in mirror M 1 with respect to the image in mirror M 2 is
Options
- A2 v sin θ
- Bv sin θ
- C3 v sin θ
- D4 v sin θ
Correct answer
A. 2 v sin θ
Step-by-step solution
Angle between v I 1 and v I 2 is 2 θ . The magnitudes of these vectors is v . ∴ | v → I 1 − v → I 2 | = v 2 + v 2 − 2 v · v · cos 2 θ = 2 v sin θ