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A biconvex lens of focal length f 1 = 10 cm is placed 40 cm in front of a concave mirror of focal length f 2 = 7.50 cm , as shown in the figure. An object, 2 cm high, is placed 20 cm to the left of the lens. The image formed by the lens, as rays travel to the right, is

Options

  1. AReal and erect
  2. BVirtual and erect
  3. CReal and inverted
  4. DVirtual and inverted

Correct answer

C. Real and inverted

Step-by-step solution

From lens equation, 1 v - 1 - 20 = 1 10 ⇒ v = + 20 cm Magnification, m 1 = v u = + 20 - 20 = - 1 Image is real, inverted, and same size as object.

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