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NTA Abhyas JEE Main2020PhysicsRay OpticsPractice

The diagram shows a spherical surface which separates two media of refractive indices, μ 1 and μ 2 , respectively. Now, a point object is placed on the principal axis as shown in the figure. Then

Options

  1. AReal image will form if μ 1 > μ 2 and for all values of u
  2. BReal image for some values of u if μ 1 > μ 2
  3. CVirtual image will form if μ 1 > μ 2
  4. DVirtual image will form if μ 1 < μ 2

Correct answer

C. Virtual image will form if μ 1 > μ 2

Step-by-step solution

&#956; 2 v - &#956; 1 - u = &#956; 2 - &#956; 1 R &#8658; v = u R &#956; 2 u &#956; 2 - &#956; 1 - R &#956; 1 &#8658; v = u R &#956; 2 u &#956; 2 - &#956; 1 u + R We can see that &#956; 1 &#62; &#956; 2 then image distance is negative which means virtual image

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