NTA Abhyas JEE Main2020PhysicsRay OpticsPractice
In a compound microscope, the objective lens and eyepiece have a focal length of 0.95 c m and 5 c m respectively and are kept at a distance of 20 c m . If the last image is formed at a distance of 25 c m from the eyepiece, calculate magnifying power.
Options
- A94
- B84
- C75
- D88
Correct answer
A. 94
Step-by-step solution
f 0 = 0.95   m = V 0 u 0 1 + D f e f e = 5   c m   u e = 25 6 For eyepiece 1 + D f e = V e U e   u = V e 6 V 0 = 20 - 25 6 = 95 6 m 0 = 95 6 - 0.95 0.95 ≈ 94 6 m n e t = 94 6 × 6 = 94