NTA Abhyas JEE Main2020PhysicsRay OpticsPractice
A flat mirror revolves at a constant angular velocity making n = 0.4 revolutions per second. With what velocity (in m s - 1 ) will a light spot move along a spherical screen with a radius of 15 m , if the mirror is at the centre of curvature of the screen?
Options
- A37.7
- B60.3
- C68.7
- D75.4
Correct answer
D. 75.4
Step-by-step solution
∵ Angular velocity of the mirror = 0.4   r e v   s - 1 = 0.4 × 2 π = 0.8 π   r a d   s - 1 ∴ Angular velocity of the reflected ray = 2 × 0.8 π = 1.6 π   ra d   s - 1 Hence, the velocity of light spot over the screen v = r ω = 15 × 1.6 π = 75.4   m   s - 1