The dimensions of (a)/(b) , in the equation P = a - t^ 2 bx , where...

P = \dfrac{a - t^{2}}{bx}$<br /><br />$⇒ Pbx = a - t^{2}$<br /><br />$⇒ \left[Pbx\right] = \left[a\right] = \left[t^{2}\right]

Or \left[b\right]$= \left[t^{2}\right]$\left[P\right]\left[x\right]$= \left[T^{2}\right]$\left[ML^{- 1}T^{- 2}\right]\left[L\right]$= \left[M^{- 1}T^{4}\right]$

$∴$\left[\dfrac{a}{b}\right] = \dfrac{ \left[T^{2}\$r$ \right]}{\left[M^{- 1}T^{4}\right]} = \left[MT^{- 2}\right]$