NTA Abhyas 2020
- Exam
- NTA Abhyas
- Year
- 2020
- Subject
- Physics
- Chapter
- Units and Dimensions
NTA Abhyas 2020 · Physics · Units and Dimensions
If force F is related with distance x and time t as F = A x + Bt^ 2...
If force is related with distance and time as , the dimensions of is
Options
- A
- B
- C
- D
Correct answer
C.
Step-by-step solution
All terms of an equation must have same dimensions
br>
\left[A\right] =\dfrac{MLT^{- 2}}{\sqrt{L}}
\left[B\right] =\dfrac{MLT^{- 2}}{T^{2}}
br>
\left[A\right] =\dfrac{MLT^{- 2}}{\sqrt{L}}
\left[B\right] =\dfrac{MLT^{- 2}}{T^{2}}